If have found the answer to my question, but I don't now why it his this name, is there sombedy that can explain me what the '1' is at the end of the classname.
Mbusrv=createobject("ModbusSrv.ModbusSrv.1")
>>>this are the classes of the library:
>>>ctcpipserver and ModbusSrv
>>>
>>>What should be the first parameter and what the second of the createobject method ?
>>
>>Click on ModbusSrv and you'll see a full name below.
>
>This is what I see when I click on ModbusSrv.
> Class ModbusSrv
> Member of MODBUSSERVERLib
>
>How can I check if this automation-server is good registerd?