>Thanks for the Answer...
>I can determine if I have a ONE or Two dimensional Array with this
>
>llTwoDimensions = alen(MyArray)#alen(MyArray,1)
>
>my problem was this:
>
>for i=1 to alen(MyArray,1)
>?MyArray(i,1) &&This always delivered the first value of 1 Dimensional Arrays
>endfor
>
>I think it still is a Bug if I get no error for this:
>
>dimension myArray(3)
>myArray(1)=1
>myArray(2)=2
>myArray(3)=3
>
>?myArray(3,1) &&Should at least give me an error but NOT the value 1
>?myArray(3,2) &&Should at least give me an error but NOT the value 2
>
>*Because Foxpro seems to use
>*myArray(1,1)=1,myArray(1,2)=2,myArray(1,3)=3
>*myArray(2,1)=1,myArray(2,2)=2,myArray(2,3)=3
>*myArray(3,1)=1,myArray(3,2)=2,myArray(3,3)=3
>*But why does alen(myArray) give me 3 then?
>?myArray(999999,3) Even gives me 3... I don't understand that.

This sort of behavior goes back at least as far as 2.x. Consider the following

DIMENSION a_foo[2]
? ALEN(a_foo, 2) && Returns zero
DIMENSION a_foo[2, 1]
? ALEN(a_foo, 2) && Returns one

This is probably the fundamental reason why you see the behavior you do. As a result

? ALEN(a_foo, 2) < 2

will also tell you whether or not you have a one or two dimensional array. If it's one dimension, you simply need one subscript. If it's two, you need two.