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To
26/12/2002 21:24:22
Hilmar Zonneveld
Independent Consultant
Cochabamba, Bolivia
General information
Forum:
Games
Category:
Mathematical
Miscellaneous
Thread ID:
00735982
Message ID:
00736078
Views:
14
7 * 11 * 13 = 1001

So, any 3 digit number which is "doubled" on itself... for example 413 - > 413413 is
essentially multiplied by 1001 - > 413 * 1001 = 413413

which is 413 * 7 * 11 * 13 = 413413 = 413 * 1001.

Tommy

>OK, more than a puzzle, this is an interesting mathematical oddity. You may want to explain how come, though.
>
>
  • Take any three-digit number (e.g.: 413).
    >
  • Repeat the digits once more (e.g.: 413413).
    >
  • Divide the resulting number by 7 (e.g.: 59059).
    >
  • Divide the result by 11 (e.g.: 5369).
    >
  • Divide the result by 13 (e.g.: 413).
    >
    >Oddity number one: dividing succesively by 7, 11, and 13, results in an integer (or, in other words, no remainder), no matter with what number you start.
    >
    >Oddity number two: you always get your original number back..
    >
    >Hilmar.
    Tommy Tillman A+ NetWork+ MCP
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