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One Odd Ball
Message
From
02/01/2003 14:58:10
 
 
To
02/01/2003 14:52:35
General information
Forum:
Games
Category:
Quiz
Title:
Miscellaneous
Thread ID:
00737451
Message ID:
00737480
Views:
22
Assuming A is not equal to B
On the second weigh
A1, C1, C2, C3 vs. B1, A2, A3, A4

>This one will have to be figured out later when I can really concentrate. The best I can do so far is:
>
>Assuming balls are labeled as follows:
>A1, A2, A3, A4
>B1, B2, B3, B4
>C1, C2, C3, C4
>
>and assuming group A and group B are not equal (1st weigh) and group A is heavier than group B, then create two new groups using the first ball from group C in the first new group with one ball from group A and one ball from group B - something like:
>
>well I'm lost! Who could figure out all of the possibilities and know from which group to pick the next ball to weigh depending on whether or not A is heavier than B, etc? A math wizard! That's not me!
>
>I give up!!!! :o)
>
>if not equal, then weigh
>>That's the first step. If you weigh A and B and they are equal, that is the simplest of the solutions. The difficult solution is when A is not equal to B.
>>
>>>I don't know this one either, but does it have something to do with breaking down the balls into 3 groups of 4 balls in each group and then comparing the weights of the each group and going on from there? It seems like mathematically it could be broken down...
>>>
>>>Tracy
>>>
>>>>You have 12 billiard balls.
>>>>
>>>>One of them is either lighter or heavier than the others.
>>>>
>>>>You can weigh the billiard balls 3 times on a balance scale.
>>>>
>>>>You need to find out which ball it is and whether it is heaver or lighter.
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