>>>>Ok, need to think more...
>>>
>>>You're thinking too much.
>>>You've got balls in group A, B and C.
>>>Two of those groups will weigh the same. The third group will weigh different. Stick to weighing more in that group.
>>
>>If A=B, then the solution is trivial. If A<>B, the solution is more complicated. Dan gave it in another thread, but I didn't think it through...
>>
>>Anyway, here is a simple problem for you.
>>
>>Two players play the game: who first says 100 will win. They can say any number between 1 and 10. Who and how will win?
>>
>>Example:
>>A - 3
>>B - 7
>>A - 9
>>B - 10
>>etc.
>
>Is this a math problem or a simple logic problem?
>My first guess is to average out each persons possible guess to 5.5 and then take that to its logical conclusion.

No, it's just a simple game. If you have somebody near you, you can play. Two players say aloud numbers, I just gave a sample of the two players and possible numbers. Each number should be greater than the previous (from 1 to 10). E.g. I can say 5, and you can say 15 (or 6,7,8, etc). The first player, who says 100 (but you can play for 200 or any number, you define), will win.

My question is: who will win, if there is a strategy in this game, and what should be this strategy?