>Hi Nick,
>
>>This is not a bug, this is by design. Tecnically there is only one image >control in the column for all visible records. When .Sparse = .t. you see >the image only in the active row when you click on another row, it becomes >active and shows the image control.
>>You want to show the different images in every record and be able to right >click and run some code for any row, correct?
>
>Yes, Do you have a suggestion or solution?

Yes, I have the second (and the most important :) half of the solution. :-)

Place into the grid column not the image control alone, but the container control with the image control in it. (You will need to create a container+image class for that). Then place your desired code into container RightClick() method and it will work. You can set column.Sparse = .F. to see all the images in the grid rows.

I assume you know how to show different images in grid rows. If not - you can do it using Dynamic... properties, for example DynamicFontBold.

form1.grid1.column1.DynamicFontBold = "thisform.ShowPicture()"

*** form1.ShowPicture() method
thisform.Grid1.column1.cntImage1.image1.Picture = your_field_with_picture_pathname
RETURN .f.

If you want, I can send you a sample form.