Assuming that the table is called Audit, I'm thinking of something like this

SELECT
...
FROM
Audit a
LEFT OUTER JOIN Audit pa ON a.eeID = pa.eeID
WHERE
pa.eeID IN (SELECT TOP 1 eeID FROM Audit a1 WHERE a1.eeID = a.eeID AND audit_datetime < a.audit_datetime)

-Mike

audit_id
, audit_datetime
, audit_imageType
, audit_username
, ee_id
, empnum
, fname
, mname
, lname

So, I want to end up with a return of:

audit_datetime
,audit_username
,ee_id_old
,ee_id_new
,empnum_old
,empnum_new
,fname_old
,fname_new







>>Do you want a clue or the answer? The clue is in rewording the problem:
>>
>>I want the first record that comes before the current audit record for the same ID.
>>
>>-Mike
>
>Right, and I have been able to write a query to get the audit_id of the record that comes before a specific audit_id record, but I am not sure how to write it to return a rs that meets a certain date range. I'd hate to resort to a cursor.
>
>So, I guess I want the answer.
>
>BOb