Yes I did.

Thanks
Simon


>Then I can assume you figured out you could enter your value from the property window as:
>

=".T."

>
>
>>Hi Fred
>>
>>I found the problem. It has to do with how the properties are interpreted when entered in the properties window. If I enter .T. the property is set to a logical type which I do no want. If I enter ".T." the property is a character type but includes the quotation marks which I do not want. What I want is a character string of three characters .T.
>>
>>I did not realize that when I entered the value with quotes the quotes would be part of the string and that is what caused the problem. I should have realized this because I have been caught by this several times in the past.
>>
>>Simon
>>
>>>>I had the following two properties set as follows:
>>>>
>>>>This.cWhereBase="PID=' '.Or.PID$This.cOpenNodes"
>>>>This.cWhereUser=".T."
>>>>
>>>>The following code fails with an error message (Function argument value, type or count is invalid.):
>>>>
>>>>Scan While .T. for Evaluate(This.cWhereBase+".And."+This.cWhereUser)
>>>>
>>>>However if I change This.cWhereUser as follows everything works fine:
>>>>
>>>>This.cWhereUser="1=1"
>>>>
>>>>In the first case in the debugger evaluate(This.cWhereUser) returns at character type expression of '.T.' when I expected a logical value.
>>>>
>>>>Is this a bug or just the way the evaluate function works? It seems like it did not evaluate the ".T."
>>>>
>>>>Thanks
>>>>Simon
>>>
>>>Seems to work OK for me when I try it.