>Quando e digo que preciso subtrair sua HORA seria
>
>17:23:01 - 16:20:01 = 01:03:00
>
a = ctot("30/05/2003 00:00:00")
b = ctot("30/05/2003 01:01:00")
minutos = iif(mod((b-a)/60, 60)=<59,mod((b-a)/60, 60),0)
hora = int(((b-a) / 60) /60)
horaeditada = transform(hora,"@L 999")+":"+transform(minutos,"@L 99")
? horaeditadaObs: Não há precisão de segundos, subtrai minutos e horas
Claudio
"Now to him who is able to do immeasurably more than all we ask or imagine, according to his power that is at work within us, Ephesians 3:20
