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Work days between two dates - finally!
Message
From
08/06/2003 14:18:56
 
 
To
08/06/2003 12:12:56
Mike Yearwood
Toronto, Ontario, Canada
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Miscellaneous
Thread ID:
00797684
Message ID:
00797797
Views:
36
When I run the code in this message with {^2003/06/06} and {^2003/06/11} I get 4. What do you get? I sure hope 4!

Glenn

>Hi Glenn
>
>I did copy your code. I made a typo in the dates I gave you. I used June 6, 2003 to June 11, 2003.
>
>
LPARAMETERS dDate1, dDate2
>LOCAL wks, wkd
>hd = MAX(ddate1,ddate2)
>ld = Min(ddate1,ddate2)
>
>wks = INT( (hd - ld)/ 7)
>
>* Return Weeks * 5 which is overal workdays
>* Adjust for starting day of the first week
>* And adjust for the last partial week
>
>RETURN ;
>    INT(wks * 5 + ;
>    IIF(DOW(ld,2) < 6, 6-DOW(ld,2),0) + ;
>    IIF(DOW(hd,2) < 6, DOW(hd,2),0) )
>
>
>>You must not have copied my code from this page because with this code I get 4, not 11. I admit 4 is incorrect but I am still debugging. I will post an improved version in a few minutes.
>>
>>Thanks for the critique
>>
>>Glenn
>>
>>C O R R E C T I O N ----
>>
>>Fri - Mon - Tue - Wed
>>
>> 4 IS correct!
>>
>>>Glenn
>>>
>>>I see you're trying something like what I posted. I like how you're trying to reduce the code's length. But, given June 11, 2003 and June 6, 2003 your version returns 11 days. Counting the days on the calendar I get 5 days.
>>>
>>>The random testing makes it impossible to determine if one routine is faster than another.
>>>
>>>>Thanks, here is a newer version which also is based upon weeks but in a different way.
>>>>
>>>>LPARAMETERS dDate1, dDate2
>>>>LOCAL wks, wkd
>>>>
>>>>hd = MAX(ddate1,ddate2)
>>>>ld = Min(ddate1,ddate2)
>>>>
>>>>wks = INT( (hd - ld)/ 7)
>>>>
>>>>* Return Weeks * 5 which is overal workdays
>>>>* Adjust for starting day of the first week
>>>>* And adjust for the last partial week
>>>>
>>>>RETURN ;
>>>>    INT(wks * 5 + ;
>>>>    IIF(DOW(ld,2) < 6, 6-DOW(ld,2),0) + ;
>>>>    IIF(DOW(hd,2) < 6, DOW(hd,2),0) )
>>>>
>>>>
>>>>
>>>>On my computer (AMD 1.6g 256mb) a 100,000 randomized test took 2.031 seconds including the considerable overhead of the test itself.
>>>>
>>>>ld = RAND(-1)
>>>>nStart = SECONDS()
>>>>FOR i = 1 TO 100000
>>>>	noffset = INT(RAND()* 36)
>>>>	ld = GOMONTH(DATE(),1-noffset)
>>>>	hd = GOMONTH(DATE(),noffset)
>>>>	wkd = workdays(ld,hd)
>>>>ENDFOR
>>>>MESSAGEBOX('Execution time was '+TRANSFORM(SECONDS()-nstart)+' seconds')
>>>>
>>>>
>>>>
>>>>What do you think of this version?
>>>>
>>>>Thanks
>>>>
>>>>Glenn
>>>>
>>>>
>>>>>Glenn,
>>>>>
>>>>>That code will fail if the dates cross a year boundary or are more than a year apart.
>>>>>
>>>>>>I needed a solution to determine the number of workdays between two dates and have not been satisfied with the prevalent techniques.
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