>Still Can't solve the problem
>I modify your list into like this :
>
>
>#Define INTERNET_MAX_PATH_LENGTH 2048
>
>PROCEDURE GetFtpDirectory
> LPARAMETERS lcDirectory
> LOCAL fResult, RemoteDir, RemoteDirLength
>
> IF THIS.OpenFtpConnection() && Open an FTP Handle
> RemoteDirLength = INTERNET_MAX_PATH_LENGTH
> RemoteDir = repl(chr(0), 2048)
>
> fResult = FtpGetCurrentDirectory(this.nConnect_Handle, @RemoteDir, @RemoteDirLength)
>
> THIS.GetExtendedError()
> LcDirectory = left(RemoteDir, RemoteDirLength)
>
>
> THIS.CloseFtpConnection()
>
> IF fResult = 1
> RETURN .T.
> ELSE
> RETURN .F.
> ENDIF
> ENDIF
>
>ENDPROC
>
>
>I Called the procedure :
>
>newDirectory = 'Testing'
>
>IF !sz_ftp.GetFtpDirectory(NewDirectory)
> MESSAGEBOX("--- Directory Exist",16,"Information")
> RETURN
>ENDIF
>
>
>But Still Can't Check the existing Drive in FTP..
>
>Any Suggestion...
>
>thx

Tut,

You should set newDirectory to '' prior to calling your sz_ftp.GetFtpDirectory(). Also, put an @ before the parameter : sz_ftp.GetFtpDirectory(@NewDirectory)

It appears to me that you are using ftpGetCurrentDirectory() to check whether a directory exists.
The vfp equivalent of ftpGetCurrentDirectory() is curdir()

If you want to know whether a directory exists, then there are two options imo

(1) FtpSetCurrentDirectory(), ie a CD, if successful it exists, if not, it does not exist

(2) make a dir() command, using FtpFindFirstFile() and successive InternetFindNextFile()


It's not clear to me what you want to do