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Sql to find duplicates
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À
17/07/2003 14:39:34
Information générale
Forum:
Visual FoxPro
Catégorie:
Codage, syntaxe et commandes
Divers
Thread ID:
00811118
Message ID:
00811229
Vues:
12
>Whoops! Mea culpa. I misread it.

No problem. What did you *think* was wrong?

>I still like this way the best as it gives all the duplicates rather than just a list of the contents >of one of the duplicated fields.

It all depends on what you need, right? <g>

Mike

>Alan
>
>>I like this way the best myself, but unfortunately, it is not ansi compliant, and won't work in VFP8 without setting enginebehavior first.
>>
>>Alan
>>
>>>Allen,
>>>
>>>How about
>>>
>>>
>>>select * from lineitems ;
>>>where lineitems_id IN (select lineitems_id from lineitems ;
>>>                       group by 1 ;
>>>                       having count(lineitems_id) > 1) ;
>>>order by lineitems_id ;
>>>into cursor curDupes
>>>
>>>
>>>
>>>>>>>>Hi,
>>>>>>>>Can someone help me with the SQL to find all duplicates in a field?
>>>>>>>>Thanks,
>>>>>>>>Allen
>>>>>>>
select KeyFld, count(*) as CntDups from TestDups group by 1 ;
>>>>>>>     having CntDups > 1 ;
>>>>>>>     into cursor curDupes
>>>>>>>
>>>>>>
>>>>>>Sorry but I did get it...
>>>>>>Keyfld for me is lineitems_id
>>>>>>TestDups table is lineitems
>>>>>>What's CntDups... a variable?
>>>>>>
>>>>>>Allen

>>>>>
>>>>>
>>>>>CntDups becomes a calculated field in your query result (cursor).
>>>>>Basically you are saying to group by "lineitems_id" and count how many show up. Then disregard the ones that show up only once and show only 2 or more instances ("having CntDups > 1").
>>>>>
>>>>>
>>>>>select lineitems_id, count(*) as CntDups ;
>>>>>from lineitems ;
>>>>>group by 1 ;
>>>>>having CntDups > 1 ;
>>>>>into cursor curDupes
>>>>>
>>>>>
>>>>>Clearer?
>>>>
>>>>Thank you. It's clearer and works but I needed another thing...
>>>>What you gave me shows the duplicate record and the times it's duplicated, but I was trying to get the duplicate records, record by record. So that each record is listed.
>>>>Thanks,
>>>>Allen
Mike C.
-------
I keep trying to find a life of my own, apart from you.
DC Talk/Charlie Peacock, In the Light.
www.risensystems.com/ra/itlbegin.rm
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