Hi Arnaldo,

If FormB is inside the MDI parent form, you need to convert the location back to the client position via parent form's PointToClient Method method.


>Thanks for your Reply!
>
>It seems I'm not understanding the way that method works, here is my portion of code.
>
>The situation is:
>I have two forms: frmA, frmB
>In frmA I have a button (btnA)
>In the Button Click I want to show the frmB form in the same location of the button.
>
>

>
>    Private Sub btnA_Click(ByVal sender As System.Object _
>    , ByVal e As System.EventArgs) Handles btnA.Click
>
>        Dim fA As New frmB()
>        Dim pA As System.Drawing.Point
>
>        pA = btnA.PointToScreen(btnA.Location)
>
>        With fA
>            .Show()
>            .Left = pA.X
>            .Top = pA.Y
>        End With
>
>    End Sub
>
>

>
>when I click the button the form shows in another position.
>
>Note: the frmA is MdiChild of another form MdiFrmA.
>
>Am I using the PointToScreen method incorrectly?
>
>Thanks again, in advance!