*!*Manually entered same number && this number not exist on floating point domain m.lnTotalAVGmanual = 58271.27004999990000 ?str(m.lnTotalAVGmanual-58271,25,16) * now you known that next number exists on floating point m.lnTotalAVGmanual= 58271.27004999989731 ?str(m.lnTotalAVGmanual-58271,25,16) * found your sum true number, removing left integer fp number *The result from SUM was determined by ?str(m.lnTotalAVG1-58271,25,16)if you compare the two decimal part of