Level Extreme platform
Subscription
Corporate profile
Products & Services
Support
Legal
Français
SELECT - SQL avoiding duplicates?
Message
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Miscellaneous
Thread ID:
00856923
Message ID:
00856929
Views:
7
Tom,

Thank you, that worked flawlessly!

-Don

>Try this:
>
>
>
>CREATE CURSOR cust (pk int, name c(10))
>CREATE CURSOR orders (pk int, date d, custfk int)
>INSERT INTO cust VALUES (1, "ADAMS")
>INSERT INTO cust VALUES (2, "BROWN")
>INSERT INTO cust VALUES (3, "COOPER")
>
>INSERT INTO orders VALUES(1, DATE()-2, 1)
>INSERT INTO orders VALUES(2, DATE()-1, 1)
>INSERT INTO orders VALUES(3, DATE(), 1)
>
>INSERT INTO orders VALUES(4, DATE()-2, 2)
>INSERT INTO orders VALUES(5, DATE()-1, 2)
>INSERT INTO orders VALUES(6, DATE(), 2)
>
>INSERT INTO orders VALUES(7, DATE()-3, 3)
>
>SELECT cust.pk, cust.name, MAX(date) FROM cust JOIN orders ON cust.pk = orders.custfk GROUP BY cust.pk, cust.name
>
>
>>I have a two tables which essentially have a one to many relationship. Let's call the first one custmrs and the second one orders. I want to have a SELECT statement will return matching results that only shows the most recent order for each customer.
>>
>>I thought I could do something like this, but it doesn't work. I get a Group By clause is missing or invalid error message. What am I doing wrong?
>>
>>SELECT * FROM custmrs JOIN orders ON custmrs.clientid = orders.clientid INTO CURSOR csrTemp ORDER BY custmrs.clientid, orders.orddate DESC GROUP BY custmrs.clientid
>>
>>Thanks,
>>Don
Don Knoup
don.knoup@ticomix.com
Ticomix, Inc.
Previous
Reply
Map
View

Click here to load this message in the networking platform