>>>>What is the easiest way to determine if a number has two decimal places and if not, append it so it will have two?
>>>

>>>nNumber = (nNumber-int(nNumber))*100
>>>if nNumber > 9
>>> return .t.
>>>endif
>>>

>>>Cetin
>>
>>Snip.... (But I donno what means!)
>>Seem wrong. if nNumber is 5.01 !!
>>or typing error.
>>
>>[if nNumber > 0 ]....
>>I perfer to use [if Empty(nNumber)]
>>
>>Well, I think it would be:
>>
>>Alltrim(Str(nNumber, 10,2))
>>
>>Make to 2 decimal string without test because cannot make 5.00 as requiry!!
>>If you want to make 5.001 to 5.01, it would be:
>>
>>Alltrim(Str(Ceiling(100*nNumber)/100, 10,2))
>>
>>It will be very useful on report and label printing!! ^_^;
>Thanks Justok,
>Seems I got the question wrong. This one might be more true :
>

>* 5,5.0,5.00,5.0049 etc would be returned as 5.00
>return round(nNumber,2)
>

>Cetin

Well, Yesterday I wonder that it may more crazy on return:

Alltrim(Str(Ceiling(100*nNumber)/100, 10,2))

e.g. 5.0000001 ==> 5.01

But it is for Price Value!! ;D===