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Find CHR(13) in a string
Message
Information générale
Forum:
Visual FoxPro
Catégorie:
Crystal Reports
Titre:
Find CHR(13) in a string
Divers
Thread ID:
00888936
Message ID:
00888936
Vues:
48
Hello,

I have an address where I would like to be able to display two different ways.

The first way is as follows:

222 Address Street
YourCity, YourState 55555

The second way is as follows:

222 Address Street, YourCity, YourState 55555

I am currently placing a CHR(13) in the string.

Is there a way, using Crystal Reports Developer version 9, to search for the CHR(13) and replace it with a space?

I have tried the REPLACE command in Crystal, but I can not get it to find the CHR(13) -- at least, I can't get the string to display all on one line.

Any ideas how to do this?
Thanks,

TFISHER
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