>>I have just done the following calculation - some way to spend a vacation, eh? If you create a method or call a function to do the following...
>>---
>>nSeconds=INT(SECONDS()+(nn*60)) && nn being the number of minutes.
>>nHours=INT(nSeconds/3600)
>>nMins=INT((nSeconds-(nHours*3600))/60)
>>IF nHours>23
>> nHours=0
>>ENDIF
>>RETURN PADL(LTRIM(STR(nHours)),2,'0')+':'+PADL(LTRIM(STR(nMins)),2,'0')
>
>This certainly looks a lot cleaner (and shorter!) than anything I was considering. Thanks much, I'll try it out (and keep it around for *next* time!)
Well Paul,
Adding further to datetime arithmetic another way of doing it :

nMinutes = 15
dtNMinutesLater = dtot(date())+seconds()+nMinutes*60
nHours = hour(dtNMinutesLater)
nMinute = minute(dtNMinutesLater)
*nSecond = sec(dtNMinutesLater)
RETURN PADL(LTRIM(STR(nHours)),2,'0')+':'+PADL(LTRIM(STR(nMins)),2,'0')

Cetin