Dear David,
thank you very mush for your help,
i can't write c/c++ languge,
wher i can put my formula (g(x)=e^-x+x-0.9)).
and p0=.01
the manual soluation is
n
....
0 p0=.01
1 p1=g(p0)=.10484
2 p2=g(p1)=.10534
3 p3=g(p2)=.10536
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