>Raul,
>
>I don't think you understand what the period delimiter does. Basically, it tells the interpeter that it should append whatever is after the . to the end of the value of the variable that you substituted.
>
>var_value=5
>x='var'
>? &x._value
>
>The ? line is the same as doing:
>?var_value
>
>The interpreter just changes the x to var, then appends the _value to it.
>

Hi:

Your example gave me another idea that helped me achieve half of what I wanted.
The way you put it I use it a lot, the problem was when the appended part
of the variable name is not known beforehand.

var_value = 5
var_name_part1 = 'var'
var_name_part2 = '_value'

I was tring:
?&var_name_part1.var_name_part2 hoping VFP would append it.

It came out to be:
?&var_name_part1.&var_name_part2

Now let's say the parts of the variable name come from functions:

var_value = 5

function get_var_name_part1()
return 'var'

function get_var_name_part1()
return '_value'

I wanted something like:
? &get_var_name_part1() + get_var_name_part2()

But it doesn't work. I just wanted to cut down the amount of instructions in a series of FOR and DO WHILE loops. The functions are needed because I can't know beforehand the actual name of the variable.

But I'll leave them as they are.
var_name = get_var_name_part1() + get_var_name_part2()
? &var_name

Thanks.