Hi Mike

I drew a triangle and relearned the process.

Given a and b ...

c = m.a / COS(ATAN(m.b/m.a))


>>Pretty interesting stuff. I think there's another way to do these calcs. Using Sin/Cos you can determine the x and y. You can build a table of sin/cos values in an array and get the value based on the angle between the two objects. This is supposed to be much faster than SQRT.
>
>Do you suppose you could post an alternate algorythm that we could compare?
>
>I used the Pythagorean theorem just because it was the simplest, my trig is sooooo rusty. :-)