Hi Hilmar,

I'm glad to help :-)

MartinJ

>I am impressed by the simplicity of this solution. I was just searching for exactly the same requirement, and found that your answer exactly solved my problem - and I thought I would have to write (or copy from the UT!) some complicated loops!
>
>>Hi Steve,
>>
>>You can use function OBJTOCLIENT():
>>

>>?OBJTOCLIENT(grid.column,2)-OBJTOCLIENT(grid,2)
>>

>>
>>
>>MartinJ
>>
>>>Hi,
>>>How can I find out the .left position of the left side of a column in a grid, so that
>>>I can line up another object on the form with this column?
>>>Thanks
>>>STeve