>what would you do if x = 89.555 and at run-time you don't know how many digits are after the '.' .
>
>>Would something like this work for you ?
>>
>>x = 89.55
>>y = INT(val(RIGHT(ALLTRIM(STR(x,50,2)),2)))

cDecStr = TRANSFORM(x-INT(x))
? SUBSTR(CHRTRAN(cDecStr,CHRTRAN(cDecStr,"0123456789",""),""),2)