Jay

The logon screen will be modal, returning T or F depending on whether the logon was successful. If successful then you can enter the rest of your code, else, bomb them out.

Here's a simple encryption algo for you, if you like. It takes the text of the input password and converts it to a number, which is what's stored in the user record. Anyone can read that number but they won't know how it was derived, e.g. how many chars were used to make it, what chars, etc. When logging in, the user's password input is merely sent through this algo and compared with the stored password number.

LPARAMETER	tcPasswordText

LOCAL		lnNoChars, lnCharNum, lnPassword

lnNoChars	= LEN( tcPasswordText)	&& Get num of chars in password expr.
lnPassword	= 0

* Get the numeric ASCII value of each char in the password
* and add it to a running total, resulting in the encrypted
* password value for storing in the table
* ____________________________
For lnCharNum = 1 to lnNoChars
	lnPassword = lnPassword + ASC( SUBSTR( tcPasswordText, lnCharNum, 1) )
Endfor

Return lnPassword

HTH

Terry