>>Mem4ToNum
>MemU4ToNum ;-)

Hi Thomas, this doubt had come also to me. where put i the U ?

Before to write i have think:

UMem4ToNum

but the memory has not formed, it is the transform code that sign or unsign it,
then i stop my mind.

Your syntax fix the issue well.

Bravo. He seems banal, but it he is not.

update: and for Mem4UToNum ?
Fabio