Dale,

For converting decimal to hexadecimal I wrote the function Dec2Hex using a substr lookup rather than any other method so it's quite quick. To convert your character based numbers see the code below.

Hope this is what you were looking for.


Regards,

Mark Austen
[Schooner Software Limited]

lcChar = "E4"
?Dec2Hex(asc(left(lcChar, 1))) + Dec2Hex(asc(right(lcChar, 1)))
*
*--------------------------------------------------------------------------
function Dec2Hex
*--------------------------------------------------------------------------
*
lparameters ;
   tnDec
*
return ;
   substr("0123456789ABCDEF", int(tnDec / 16) + 1, 1) + ;
   substr("0123456789ABCDEF", (tnDec % 16) + 1, 1)
*
*
*--------------------------------------------------------------------------
*--------------------------------------------------------------------------