>>int(10/3) gives you the first three parts, i.e., 3.
>>
>>10 % 3 - or the equivalent, mod(10, 3), gives you the remainder.
>>
>>Or, using your variables:
>>
>>All numbers but the last are equal to
int (v / (n-1))>>
>>The last number is
v % (n-1)>
>Try with n=2 Expected is (5,5).
I expect the remainder of an integer division by "x" to be in the range 0 to (x-1). AFAIK, this is exactly what VFP does.
If something else is required, additional adjustments have to be done.
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