Hi Hilmar
But I think this approach will give me 4 numbers. There must be only three.
That's what makes it tricky. :-)
>>int(10/3) gives you the first three parts, i.e., 3.
>>
>>10 % 3 - or the equivalent, mod(10, 3), gives you the remainder.
>>
>>Or, using your variables:
>>
>>All numbers but the last are equal to
int (v / (n-1))>>
>>The last number is
v % (n-1)>
>Alternatively, you could calculate the remainder by subtracting the sum of the first (n-1) numbers, from the original number.
Charles Hankey
Though a good deal is too strange to be believed, nothing is too strange to have happened.
- Thomas Hardy
Half the harm that is done in this world is due to people who want to feel important. They don't mean to do harm-- but the harm does not interest them. Or they do not see it, or they justify it because they are absorbed in the endless struggle to think well of themselves.
-- T. S. Eliot
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Liberty is a well-armed sheep contesting the vote.
- Ben Franklin
Pardon him, Theodotus. He is a barbarian, and thinks that the customs of his tribe and island are the laws of nature.
