Hi
INT() returns integer part of a numeric expression

Use (INT(iv)=iv) as test condition

>I want to check if the value is integer.
>why do I get a error in the following syntax:
>

create cursor labn (labnumber c(11))
>for i=1201 to 1288
>	ci=alltrim(str(i))
>	insert into labn values ('B'+ci)
>endfor
>create cursor labn2 (labnumber c(11))
>select labn
>i=0
>scan
>	i=i+1
>	insert into labn2 values (labn.labnumber)
>	iv=i/11
>	if int(iv)&&here I get a error
>		insert into labn2 value('Narker')
>		insert into labn2 value('Roller')
>	endif
>endscan
>select labn2
>brow

>Thank you