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How to calculate elapsed time
Message
From
24/05/2005 19:36:09
 
General information
Forum:
Visual FoxPro
Category:
Other
Environment versions
Visual FoxPro:
VFP 8 SP1
Miscellaneous
Thread ID:
01016916
Message ID:
01017337
Views:
17
>>>>>Wow <g>. I didn't even think of that. I need to learn to find simple solutions myself and not to bother people with my silly questions.
>>>>>Thank you very much.
>>>>
>>>>Don't worry, there is no problem to ask if you don't know something.
>>>>
>>>>BTW, if you want to format the difference so that it also appears as a DateTime value, you might add it to a midnight DT value. The date part, of course, would be irrelevant.
>>>
>>>No, I need the result in seconds (actually in hours which is easy to convert).
>>>Thank you very much.
>>
>>What's to convert?
>>
>>cTime = TTOC({^2005/01/01 00:00}+nSeconds,2)
>>
>>Take whatever portion of it you need with LEFT() or SUBSTR().
>
>Fred,
>
>I am no sure I understand your suggestion. I was looking for a way to find difference between two T-type values in hours. Hilmar's suggestion works very well. But I don't see how the method you show will help me. What am I missing?
>
>Thank you for your suggestion.

Once you get the difference between the two datetime type values, you have seconds. To convert the seconds to time format, use what I posted above.

t1 = DATETIME()
*
* wait some amount
*
t2 = DATETIME()

nSeconds = t2 - t1
cTime = TTOC({^2005/01/01 00:00}+nSeconds,2)
Fred
Microsoft Visual FoxPro MVP

foxcentral.net
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