>>>>>>Wow <g>. I didn't even think of that. I need to learn to find simple solutions myself and not to bother people with my silly questions.
>>>>>>Thank you very much.
>>>>>
>>>>>Don't worry, there is no problem to ask if you don't know something.
>>>>>
>>>>>BTW, if you want to format the difference so that it also appears as a DateTime value, you might add it to a midnight DT value. The date part, of course, would be irrelevant.
>>>>
>>>>No, I need the result in seconds (actually in hours which is easy to convert).
>>>>Thank you very much.
>>>
>>>What's to convert?
>>>
>>>cTime = TTOC({^2005/01/01 00:00}+nSeconds,2)
>>>
>>>Take whatever portion of it you need with LEFT() or SUBSTR().
>>
>>Fred,
>>
>>I am no sure I understand your suggestion. I was looking for a way to find difference between two T-type values in hours. Hilmar's suggestion works very well. But I don't see how the method you show will help me. What am I missing?
>>
>>Thank you for your suggestion.
>
>Once you get the difference between the two datetime type values, you have seconds. To convert the seconds to time format, use what I posted above.
>
>t1 = DATETIME()
>*
>* wait some amount
>*
>t2 = DATETIME()
>
>nSeconds = t2 - t1
>cTime = TTOC({^2005/01/01 00:00}+nSeconds,2)

Fred and Cetin,

Now I understand what you guys were suggesting. I probably didn't put my question correctly, initially. What I wanted is simply the difference between two times in hours, in a numeric format. Like using it as a stop watch. For example, if I start a process at 10 pm and finish it at 1:30 am next day, I need to know that the elapsed time is 3.5 hours. And I understand that the subtracting one DateTime type from another will take into account the date change and will give me 12600 seconds.

Thank you for the explanation and your help.