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Setting the datetime to a time in the future
Message
From
23/05/2006 06:44:25
 
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Environment versions
Visual FoxPro:
VFP 8
OS:
Windows XP SP1
Network:
Windows 2000 Server
Database:
Visual FoxPro
Miscellaneous
Thread ID:
01124202
Message ID:
01124211
Views:
14
>>>>I have a datetime field named scheduled. I would like to replace the contents of the field with the next time the clock is 9 a.m in the morning. So if the datetime were say 23/05/2006 10:36:42
>>>>I would like to replace the value with 24/05/2006 09:00:00.
>>>>
>>>>Can anybody help me please?
>>>>
>>>>Thanks
>>>
>>>NewDateTime = DateTimeField + (24*60*60)
>>>? DATETIME(YEAR(NewDateTime), MONTH(NewDateTime), DAY(NewDateTime),9,0,0)
>>>
>>>** or
>>>NewDateTime = TTOD(DateTimeField) + 1
>>>? DATETIME(YEAR(NewDateTime), MONTH(NewDateTime), DAY(NewDateTime),9,0,0)
>>>
>>
>>I was thinking in the same lines, but then an easier solution "hit me in the head". :-)
>>?Datetime() -Seconds() + (33*60*60) && 33=24+9
>
>Yes, this is great, but If the DateTime value is stored in a field then you couldn't get SECONDS() so easily :-)
>Imagine that the field contains:
>01/01/2006 12:33:55, then your method will works only if it is executed at 12:33:55 ;-)

What about this solution?
?Dtot(ttod(yourfield))+(33*60*60)
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