>>Take it to its simplest: if you toss a coin, it's 1:2 you'll get a heads.
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>>Next toss it's not 1:4 you'll get heads, then for a third 1:16 (1:8 or whatever) - it's still 1:2. By the end of 64 tosses, by that logic, like the old grains of sand on a chessboard conundrum, the chances of getting heads would be practically infinity:1.
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>Yes, but if the question is whether tossing twice, you'll get two heads, then the odds are 1 in 4.

No. The odds of tossing twice and getting 2 heads is 50/50 because they are two independent events regardless of how you would like them not to be. The odds of tossing 2 coins at once and having them both come up heads is calculated differently and is 1 in 4.

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>The odds of a particular person winning twice are lower than the odds of that person winning once. That's the math I was showing.
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>However, having already won once, the odds of winning again are the same as they are for anyone else.
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>Tamar