>>I can use type for if there is a field in table:
>>
>>

?type("mytable.myfield")="U"

>>
>>but with vartype
>>
>>

?vartype("mytable.myfield")="U"

>>
>>is generates variable not found. Isn't that a bug?
>
>Here's what we said in HackFox about this:
>
>"Because VARTYPE() explicitly passes the expression to test as a parameter, it fails if an expression cannot be evaluated, causing an error 12, "Variable not found"—you'll still want to use TYPE() to check if a variable exists."
>

Which leaves the usefulness of VARTYPE() open to question.