>What is the simplest (or just simple) way of calculating time difference in minutes? For example,
>
>

>*-- Store current Hours and Minutes portion of time
>nTime1 = substr(time(),1,5)
>*-- Store another time on Hours and Minutes
>nTime2 = substr(time(),1,5)
>

>
>Given that both time() reading were done in the same day, what is the difference between nTime2 and nTime1
>in minutes? (Note that I cannot use the Seconds() function)
>
>Thank you in advance for any help.

nTime1  = substr(time(),1,5)

*** Another time
nTime2 = substr(time(),1,5)
ltTime1 = DTOT(DATE())+VAL(LEFT(nTime1,2))*3600 + VAL(RIGHT(nTime1,2))*60
IF nTime1 > nTime2
   ltTime2 = DTOT(DATE()+1)+VAL(LEFT(nTime2,2))*3600 + VAL(RIGHT(nTime2,2))*60
ELSE
   ltTime2 = DTOT(DATE()+1)+VAL(LEFT(nTime2,2))*3600 + VAL(RIGHT(nTime2,2))*60
ENDIF
? ltTime2 - ltTime1 && Result in seconds