>>What is the simplest (or just simple) way of calculating time difference in minutes? For example,
>>
>>
>>*-- Store current Hours and Minutes portion of time
>>nTime1 = substr(time(),1,5)
>>*-- Store another time on Hours and Minutes
>>nTime2 = substr(time(),1,5)
>>
>>
>>Given that both time() reading were done in the same day, what is the difference between nTime2 and nTime1
>>in minutes? (Note that I cannot use the Seconds() function)
>>
>>Thank you in advance for any help.
>
>
>nTime1 = substr(time(),1,5)
>
>*** Another time
>nTime2 = substr(time(),1,5)
>ltTime1 = DTOT(DATE())+VAL(LEFT(nTime1,2))*3600 + VAL(RIGHT(nTime1,2))*60
>IF nTime1 > nTime2
> ltTime2 = DTOT(DATE()+1)+VAL(LEFT(nTime2,2))*3600 + VAL(RIGHT(nTime2,2))*60
>ELSE
> ltTime2 = DTOT(DATE()+1)+VAL(LEFT(nTime2,2))*3600 + VAL(RIGHT(nTime2,2))*60
>ENDIF
>? ltTime2 - ltTime1
>
Thank you. I didn't think of converting to seconds and calculating the difference in seconds and then converting to minutes. I appreciate your help.
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