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Getting from distance for geography coordinates
Message
De
22/11/2011 11:40:52
 
 
Information générale
Forum:
Microsoft SQL Server
Catégorie:
Syntaxe SQL
Versions des environnements
SQL Server:
SQL Server 2008
Application:
Web
Divers
Thread ID:
01529492
Message ID:
01529529
Vues:
28
>
>;with cte as (SELECT Client.Numero, 3958.75586574*ACOS(
> CASE WHEN SIN(@Latitude3/57.2957795130823)*SIN(Client.Latitude/57.2957795130823)+
>           COS(@Latitude4/57.2957795130823)*COS(Client.Latitude/57.2957795130823)*
>           COS(Client.Longitude/57.2957795130823-@Longitude3/57.2957795130823)<-1
>           THEN -1
>      WHEN SIN(@Latitude5/57.2957795130823)*SIN(Client.Latitude/57.2957795130823)+
>           COS(@Latitude6/57.2957795130823)*COS(Client.Latitude/57.2957795130823)*
>           COS(Client.Longitude/57.2957795130823-@Longitude4/57.2957795130823)>1
>           THEN 1
>      ELSE SIN(@Latitude7/57.2957795130823)*SIN(Client.Latitude/57.2957795130823)+
>           COS(@Latitude8/57.2957795130823)*COS(Client.Latitude/57.2957795130823)*
>           COS(Client.Longitude/57.2957795130823-@Longitude5/57.2957795130823)
> END) as Distance
>
>FROM dbo.Client
>
>
> WHERE (Client.Latitude>=@Latitude-250/111.0 AND Client.Latitude<=@Latitude2+250/111.0) AND
>(Client.Longitude>=@Longitude-250/111.0 AND Client.Longitude<=@Longitude2+250/111.0) )
>
>select * from cte where Distance <=250
Thanks, I am always trying to avoid that syntax as it makes it more difficult to migrate to another backend.
Michel Fournier
Level Extreme Inc.
Designer, architect, owner of the Level Extreme Platform
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