clear s = seconds() for x = 1 to 1000000 =strtran('smith, charles', ',', '') endfor ?seconds() - s s = seconds() for x = 1 to 1000000 =chrtran('smith, charles', ',', '') endfor ?seconds() - sI always get nearly a third the time. But this is with one occurence and one character, so you are probably correct (whats new? :-), but in Seans question, CHRTran() would be a better faster choice.