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Math problem
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À
04/04/2001 13:07:17
Information générale
Forum:
Politics
Catégorie:
Autre
Titre:
Divers
Thread ID:
00491917
Message ID:
00492004
Vues:
10
>>>HI!
>>>
>>>I've got this :
>>>
>>>
>>>log6 N = (1/2)log6 64
>>>
>>>
>>>I want to find 'N'
>>>
>>>Somebody can help me?
>>
>>My guess, N=1
>
>Hi
>
>Can you show me how you got this anwser?
>
>Cause my problem is with the 'log', I don't remember how to use them properly...

OK, let me correct myself
The rule is: n*Log6(B) = Log6((B)**n)
Then
1. log6 N = (1/2)log6 64
2. log6 N = log6 (64**(1/2))
3. N = (64**(1/2))
4. N= 8
Please, correct me if I'am wrong.

HTH, Igor
Igor Gelin
Database Developer
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