>>>>HI!
>>>>
>>>>I've got this :
>>>>
>>>>
>>>>log6 N = (1/2)log6 64
>>>>
>>>>
>>>>I want to find 'N'
>>>>
>>>>Somebody can help me?
>>>
>>>My guess, N=1
>>
>>Hi
>>
>>Can you show me how you got this anwser?
>>
>>Cause my problem is with the 'log', I don't remember how to use them >properly...
>
>OK, let me correct myself
>The rule is: n*Log6(B) = Log6((B)**n)
>Then
>1. log6 N = (1/2)log6 64
>2. log6 N = log6 (64**(1/2))
>3. N = (64**(1/2))
>4. N= 8
>Please, correct me if I'am wrong.
>
>Hope this helps, Igor

Hi!!

You're right and I'm wrong

I think I will re-read my old math book!

Thanks a lot Igor!