>>>>>HI!
>>>>>
>>>>>I've got this :
>>>>>
>>>>>
>>>>>log6 N = (1/2)log6 64
>>>>>
>>>>>
>>>>>I want to find 'N'
>>>>>
>>>>>Somebody can help me?
>>>>
>>>>My guess, N=1
>>>
>>>Hi
>>>
>>>Can you show me how you got this anwser?
>>>
>>>Cause my problem is with the 'log', I don't remember how to use them >properly...
>>
>>OK, let me correct myself
>>The rule is: n*Log6(B) = Log6((B)**n)
>>Then
>>1. log6 N = (1/2)log6 64
>>2. log6 N = log6 (64**(1/2))
>>3. N = (64**(1/2))
>>4. N= 8
>>Please, correct me if I'am wrong.
>>
>>Hope this helps, Igor
>
>Hi!!
>
>You're right and I'm wrong
>
>I think I will re-read my old math book!
>
>Thanks a lot Igor!

As far as I remember math, log₆64 means 6^x=64, where log=x. So, Igor's explanation is correct and N=8.
In this case x would be 26 (not lg or ln)

HTH

If it's not broken, fix it until it is.


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