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ThisForm.ActiveControl Returns Not An Object
Message
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Miscellaneous
Thread ID:
00510492
Message ID:
00510613
Views:
11
>>Following on Larry's coattails,
>>
>>>>IF TYPE("ThisForm.ActiveControl.Name") = "C" will return .T. if ActiveControl is a valid object with a Name property. Do not use Vartype() for this as it is not robust enough for the checking and it will throw an error.
>>
>>The same can be done with variables.>>
>>
>>
>>While
>>TYPE("ThisForm.ActiveControl.Name") = "C"
>>
>>is functionally similar to
>>TYPE("ThisForm.ActiveControl") = "O"
>>
>>testing agains the .Name property of an object is more robust than testing against the object itself. It sure looks weird though.
>>
>>Regards,
>>Thom C.
>
>One exclusion though - the object created with SCATTER NAME command does not have .Name property.

Not unless you've got a field called "Name" in the table it was created from. < g >
Fred
Microsoft Visual FoxPro MVP

foxcentral.net
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