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ThisForm.ActiveControl Returns Not An Object
Message
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Miscellaneous
Thread ID:
00510492
Message ID:
00510692
Views:
12
>>>Following on Larry's coattails,
>>>
>>>>>IF TYPE("ThisForm.ActiveControl.Name") = "C" will return .T. if ActiveControl is a valid object with a Name property. Do not use Vartype() for this as it is not robust enough for the checking and it will throw an error.
>>>
>>>The same can be done with variables.>>
>>>
>>>
>>>While
>>>TYPE("ThisForm.ActiveControl.Name") = "C"
>>>
>>>is functionally similar to
>>>TYPE("ThisForm.ActiveControl") = "O"
>>>
>>>testing agains the .Name property of an object is more robust than testing against the object itself. It sure looks weird though.
>>>
>>>Regards,
>>>Thom C.
>>
>>One exclusion though - the object created with SCATTER NAME command does not have .Name property.
>
>Not unless you've got a field called "Name" in the table it was created from. < g >

Yeah, and that field-property might be numeric or logical or whatever else. :)
Nick Neklioudov
Universal Thread Consultant
3 times Microsoft MVP - Visual FoxPro

"I have not failed. I've just found 10,000 ways that don't work." - Thomas Edison
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