Thank you so much!


>>Hi guys
>>
>>help me out
>>
>>if 2^x = y, then x = ?
>>
>>thank you
>
>

>2^x = y
>
>Taking logs on both sides (I will use natural logarithms, but any base will do):
>
>ln 2^x = ln y
>
>The left side can be changed, using standard properties of logarithms:
>
>x ln 2 = ln y
>
>Now, you only require the most basic algebra to change this to:
>
>x = ln y / ln 2
>
>In VFP:
>
>x = log(y) / log(2)
>

>
>HTH, Hilmar.
>
>BTH, I suggest to use more meaningful titles.