Well, you are welcome.
BTW, I find it interesting that there are relatively few questions related to algebraic transformations, and algorithms in general.
Hilmar.
>Thank you so much!
>
>
>>>Hi guys
>>>
>>>help me out
>>>
>>>if 2^x = y, then x = ?
>>>
>>>thank you
>>
>>
>>2^x = y
>>
>>Taking logs on both sides (I will use natural logarithms, but any base will do):
>>
>>ln 2^x = ln y
>>
>>The left side can be changed, using standard properties of logarithms:
>>
>>x ln 2 = ln y
>>
>>Now, you only require the most basic algebra to change this to:
>>
>>x = ln y / ln 2
>>
>>In VFP:
>>
>>x = log(y) / log(2)
>>
>>
>>HTH, Hilmar.
>>
>>BTH, I suggest to use more meaningful titles.
Difference in opinions hath cost many millions of lives: for instance, whether flesh be bread, or bread be flesh; whether whistling be a vice or a virtue; whether it be better to kiss a post, or throw it into the fire... (from Gulliver's Travels)
