Yes, I tested under VFP 7 before I posted my code. The only case it doesn't work if there are only 0's after decimal point.

>If so, this was a behavior change in TRANSFORM() function. Are you sure?
>
>>Actulay it works in VFP 7.
>>
>>>Nope, this would not work. This was my original solution too.
>>>
>>>
>>>>>Hi everyone,
>>>>>
>>>>>I've checked old messages, but didn't find a solution for this problem: I need to find out the number of digits in a number. Say, I have 12.3456000 - the number of digits should be seven. I don't see a simple solution, so may be you can advise?
>>>>>
>>>>>Thanks a lot in advance.
>>>>
>>>>Would this do?

lnNumber = 12.3456000
>>>>IF AT( ".", TRANSFORM(lnNumber)) = 0
>>>>  lnDp = 0
>>>>ELSE
>>>>  lnDp = LEN(TRANSFORM(lnNumber)) - AT( ".", TRANSFORM(lnNumber))
>>>>ENDIF
>>>>* or in one line
>>>>lnDp = IIF( AT( ".", TRANSFORM(lnNumber)) = 0, 0, LEN(TRANSFORM(lnNumber)) - AT( ".", TRANSFORM(lnNumber)))
>>>>