Sergey,

Is it listed under function behavior change? It's important, because in VFP6.0 trailing 0's are truncated. Try ?transform(12.344000), ?transform(33.3300000000), etc.

>Yes, I tested under VFP 7 before I posted my code. The only case it doesn't work if there are only 0's after decimal point.
>
>>If so, this was a behavior change in TRANSFORM() function. Are you sure?
>>
>>>Actulay it works in VFP 7.
>>>
>>>>Nope, this would not work. This was my original solution too.
>>>>
>>>>
>>>>>>Hi everyone,
>>>>>>
>>>>>>I've checked old messages, but didn't find a solution for this problem: I need to find out the number of digits in a number. Say, I have 12.3456000 - the number of digits should be seven. I don't see a simple solution, so may be you can advise?
>>>>>>
>>>>>>Thanks a lot in advance.
>>>>>
>>>>>Would this do?

lnNumber = 12.3456000
>>>>>IF AT( ".", TRANSFORM(lnNumber)) = 0
>>>>>  lnDp = 0
>>>>>ELSE
>>>>>  lnDp = LEN(TRANSFORM(lnNumber)) - AT( ".", TRANSFORM(lnNumber))
>>>>>ENDIF
>>>>>* or in one line
>>>>>lnDp = IIF( AT( ".", TRANSFORM(lnNumber)) = 0, 0, LEN(TRANSFORM(lnNumber)) - AT( ".", TRANSFORM(lnNumber)))
>>>>>